(x^2+112)+(16x+131)=0

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Solution for (x^2+112)+(16x+131)=0 equation: 



(x^2+112)+(16x+131)=0

We get rid of parentheses

x^2+16x+112+131=0

We add all the numbers together, and all the variables

x^2+16x+243=0

a = 1; b = 16; c = +243;
Δ = b2-4ac
Δ = 162-4·1·243
Δ = -716
Delta is less than zero, so there is no solution for the equation

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